Cavitation Limitations on Valve
Pressure Drop A valve selected with too high a pressure drop can cause
erosion of discs and wire drawing of the seat. In addition,
cavitation can cause noise, damage to the valve trim (and
possibly the body) and choke the flow through the valve.
Do not exceed the maximum differential pressure (pressure
drop) for the valve selected.
The following formula can be used on higher temperature
water systems, where cavitation could be a problem, to
estimate the maximum allowable pressure drop across the
valve: Pm = 0.5 (P1 - Pv) Pm = Maximum allowable pressure drop
P1 = Absolute inlet pressure (psia)
Pv = Absolute vapor pressure (refer to Vapor
Pressure of Water Table or Steam Table)
Note: Add 14.7 psi to gauge supply pressure to obtain
absolute pressure value.
For example, if a valve is controlling 200ºF water at an inlet
pressure of 18 psig, the maximum pressure drop allowable
would be:
Pm = 0.5 [(18 + 14.7) - 11.53] = 10.6 psi
(Vapor pressure of 200ºF water is 11.53 psi)
If the pressure drop for this valve is less than 10.6 psi,
cavitation should not be a problem.
Systems where cavitation is shown to be a problem can
sometimes be redesigned to provide lower inlet velocities.
Valves having harder seat materials should be furnished if
inlet velocities cannot be lowered.
Cv (Flow Coefficient) Determination The Water Valve Sizing Table or Slide Rule (refer to the following
page) is based on the following formula:

Where: Cv = Coefficient of flow
Cv is defined as the flow in GPM with ΔP = 1 psi
GPM = US gallons per minute (60ºF, 15.6ºC)
ΔP = Differential pressure in psi (pressure drop) |
|
Other variations of this formula are:

These formulas can be used to calculate one of the three
quantities if the other two are known.
Flow coefficients (Cv’s) for valve bodies are given on valve
specification pages of this catalog.
Metric (SI) Units Kvs is defined as the flow in m3/h with ΔP = 100 kPa (1.0
Bar) with the valve completely open.
Flow is calculated using the following formula: 
ΔP = Differential pressure (pressure drop) in Bar
(1 Bar = 100 kPa)
m3/h = Cubic meters/hour (15.6 °C)
Pressure drop is calculated using the following form of the
above formula: 
These formulas can be used to calculate one of the three
quantities if the other two are known.
| Water Temperature ºF |
Vapor Pressure psig |
Water Temperature ºF |
Vapor Pressure psig |
| 40 |
0.12 |
140 |
2.89 |
| 50 |
0.18 |
150 |
3.72 |
| 60 |
0.26 |
160 |
4.74 |
| 70 |
0.36 |
170 |
5.99 |
| 80 |
0.51 |
180 |
7.51 |
| 90 |
0.70 |
190 |
9.34 |
| 100 |
0.95 |
200 |
11.53 |
| 110 |
1.28 |
210 |
14.12 |
| 120 |
1.69 |
220 |
17.19 |
| 130 |
2.22 |
230 |
20.78 |
|